The answer is G=34 !!!!!!
Answer:
the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
Step-by-step explanation:
Given the data in the question;
μ_x = 10 pound bags
standard deviation s_x = 0.24 pounds
sample size n = 4
The bag weights are normally distributed so;
p( x' less than 9.8 ) will be;
p( (x'-μ_x' / s_x') < (9.8-μ_x' / s_x') )
we know that;
μ_x' = μ_x = 10
and s_x' = s_x/√n = 0.24/√4
so; we substitute
p( z < ( (9.8 - 10) / (0.24/√4) )
p( z < -0.2 / 0.12 )
p( z < -1.67 )
{ From z-table }
⇒ p( z < -1.67 ) = 0.0475 ≈ 0.05
Therefore, the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
for 5 lb. bag = $6.76
so, for 1 lb. bag = 6.76/5 = $1.35
So, unit prize is $1.35 per pound.
Answer:
C. (x + 4)(x + 5).
Step-by-step explanation:
We need 2 numbers whose product is + 20 and whose sum is + 9.
They are + 5 and + 4 , so
x2 + 9x +20
= (x + 4)(x + 5).
