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jolli1 [7]
3 years ago
13

2(4x+4) BRO I NEED HELP

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0
8x + 8 —————// hope it helps
viktelen [127]3 years ago
7 0
8x +8! I hope this helps u a lot
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Two cities are 3450 miles apart. A plane leaves one of​ them, traveling towards the other at an average speed of 310 miles per h
Amiraneli [1.4K]

Answer:

5 hours.

Step-by-step explanation:

let they meet after t hours.

310t+380t=3450

690t=3450

69t=345

t=345/69=5

8 0
3 years ago
I need help please!!!!!
charle [14.2K]
Obtuse angle. If wrong I’m sorry lol
5 0
3 years ago
Oshua's mother has a family Christmas gathering at 2:00. Joshua must travel 348 miles to join the festivities. He left his house
gavmur [86]

Answer:

58 miles/hour

Step-by-step explanation:

Given that the family Christmas gathering has been scheduled at 2:00 p.m.,

and Joshua left the house at 8:00 a.m.

So, the total time available in order to arrive on time to attend the Christmas gathering, t=6 hours

The total distance, Joshua has to travel, d= 348 miles.

As average speed= (total distance)/(total time)

So, the average speed of driving = 348/6=58 miles/hour

Hence, Joshua must drive at an average speed of 58 miles/hour in order to arrive on time.

7 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
4 years ago
Dora took 10 hours to walk a 30 mile trail how long did it take her to walk 9 miles going the same speed?
Brrunno [24]
3 hours
3 \times 10 = 30 \: so \: it \: is \: 3 \:  mph \: 3 \times 3 = 9
6 0
4 years ago
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