Question

Show your work please!​

Answer 1

Answer:

$(\dfrac{1}{4})^{\dfrac{-3}{2}}$ = 8

Step-by-step explanation:

The given expression is :

$(\dfrac{1}{4})^{\dfrac{-3}{2}}$

We know that,

$\dfrac{1}{x}=x^{-1}$

So,

$(\dfrac{1}{4})^{\dfrac{-3}{2}}=(\dfrac{1}{2^2})^{\dfrac{-3}{2}}\\\\=(2^{-2})^{\dfrac{-3}{2}}\\\\=(2^{-1})^{-3}\\\\=2^3\\\\=8$

So, the value of the given expression is 8.