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2 years ago

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NWMS has 840 students. Ben surveys a random sample of 60 students and finds that 8 of them have more than 3 siblings. How many s

tudents at the school are likely to have more than 3 sibling

1 answer:

Murrr4er [49]2 years ago

7 0

Answer:

the answer is 196

Step-by-step explanation:

hope this helps

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Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the

ludmilkaskok [199]

By Stokes' theorem,

$\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$

where $\mathcal C$ is the circular boundary of the hemisphere $\mathcal M$ in the $y$ - $z$ plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

$\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle$

where $0\le t\le2\pi$ . Then the line integral is

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi$

We can check this result by evaluating the equivalent surface integral. We have

$\nabla\times\mathbf f=\langle1,0,0\rangle$

and we can parameterize $\mathcal M$ by

$\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle$

so that

$\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv$

where $0\le v\le\dfrac\pi2$ and $0\le u\le2\pi$ . Then,

$\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi$

as expected.

7 0

3 years ago

Y is in direct proportion to x. x = 25, y = 5. Find the value of y, if x = 9.

Sholpan [36]

Answer:bh

345

Step-by-step explanation:

y is in direct proportion to x. x = 25, y = 5. Find the value of y, if x = 9.

8 0

2 years ago

Read 2 more answers

- 3x + 9 - 4 = x + 3 + 2x

Gwar [14]

-3x + 9 - 4 = x + 3 + 2x
-3x + 9 - 4 = 3x + 3
9 - 4 = 6x + 3
5 = 6x + 3
2 = 6x
1/3 = x

6 0

3 years ago

Read 2 more answers

Show all work to identify the asymptotes and state the end behavior of the function f(x)=3x/x-9

lorasvet [3.4K]

Using the asymptote concept, we have that:

The vertical asymptote is x = 9.

The horizontal asymptote is y = 3.

The end behavior is that as $x \rightarrow \infty, y \rightarrow 3$ .

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{3x}{x - 9}$

For the vertical asymptote, we have that:

x - 9 = 0 -> x = 9.

For the horizontal asymptote:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{3x}{x - 9} = \lim_{x \rightarrow \infty} \frac{3x}{x} = \lim_{x \rightarrow \infty} 3 = 3$

Hence, the end behavior is that as $x \rightarrow \infty, y \rightarrow 3$ .

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

8 0

1 year ago

-(18+4x)=8 hope you can help

Step2247 [10]

-1(18+4x)=8
Then you distribute
-18-4x=8
-4x=26
X= -6.5

4 0

3 years ago

Read 2 more answers