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3 years ago

Which equation is perpendicular to the line y=5x-9

Mathematics

1 answer:

Soloha48 [4]3 years ago

4 0

Answer:

The format of the equation of a line is y=mx+c so in order to know whether which line is perpendicular to line y=5x-9, gradient of y=5x-9,which is 5,has to multiply by another gradient to get -1.[in short m1×m2=-1]

So the equation perpendicular to line y=5x-9 has a gradient of -1÷5=-1/5

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How many solutions does this equation have?

Greeley [361]

Answer:

No solution

Explanation:

-4+19-7f = -15-7

cancel terms on both sides ( add 7f on both sides)

Calculate the sum

-4+19= -15

-4+19=15

15 = -15

The statement 15 = -15 is false so there is no solution :)

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Answer:kk

Step-by-step explanation:

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Salsk061 [2.6K]

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4 years ago

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Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1. (2 points)

umka2103 [35]

Focus of the parabola is (-5,5) and directrix is y = -1.

Let's assume a point (x,y) on parabola.

According to definition of parabola, the distance between point (x,y) and focus (-5,5) would be same as the distance between the point (x,y) and directrix y = -1.

$\sqrt{(x+5)^2+(y-5)^2} = \sqrt{(y+1)^2} \\\\(x+5)^2+(y-5)^2=(y+1)^2 \\\\(x+5)^2 + y^2 - 10y +25 = y^2 +2y +1 \\\\(x+5)^2 = -y^2 +10y -25 + y^2 +2y +1 \\\\(x+5)^2 = 12y -24 \\\\12y = (x+5)^2 +24 \\\\ y = \frac{1}{12} (x+5)^2 +2$

Hence, option D is correct, i.e. f(x) = one twelfth (x + 5)2 + 2.

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3 years ago

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