Which number line shows the solution set for |8-2p|=6?

Solve for X

satela [25.4K]

Answer:

3) 16

Step-by-step explanation:

these are alternate-interior angles which are congruent

10x-23 = 137

10x = 160

x = 16

4 0

3 years ago

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Simplify 10 times the square root of quantity 3 x end quantity plus 4 times the square root of quantity 3 x end quantity plus 5

gladu [14]

$\\ \rm\dashrightarrow10\sqrt{3x}+4\sqrt{3x}+5\sqrt{3x}+9\sqrt{3x}+9\sqrt{6x}+19\sqrt{3x}+19\sqrt{9x^3}$

$\\ \rm\dashrightarrow (10+4+5+9+19)\sqrt{3x}+9\sqrt{6x}+19\sqrt{3^2x^2x}$

$\\ \rm\dashrightarrow 47\sqrt{3x}+9\sqrt{2x}\sqrt{3x}+57x\sqrt{x}$

$\\ \rm\dashrightarrow (47+9\sqrt{2x})\sqrt{3x}+57x\sqrt{x}$

3 0

2 years ago

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What is the answer to 36+42=6(6+□)

Vsevolod [243]

Answer:

7

Step-by-step explanation:

36+42=6(6+□)

78= 6 (6+n)

78/6 = 6/6 (6+n)

13=(6+n)

13-6 = (6-6 +n)

7= n

4 0

3 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

Vesnalui [34]

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

$\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.$

Since

AB=4;
A'B'=10;
AC=6;
A'C'=15,

then the scale factor of the dilation is

$k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.$

3 0

3 years ago

According to a 2009 Reader's Digest article, people throw away approximately 11% of what they buy at the grocery store. Assume t

expeople1 [14]

Answer:

0.14% probability that the sample proportion exceeds 0.2

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .