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Oksanka [162]
3 years ago
10

i need step by step answer

Mathematics
1 answer:
shusha [124]3 years ago
3 0
Please like if this was helpful :) ?

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HEY, CAN SOMEONE PLEASE HELP WITH THIS QUESTION???
stellarik [79]

Answer:

five thousand one hundred seventy nine

Step-by-step explanation:

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In constructing a box-and-whisker plot from a data set, which values are at the ends of the box?
I am Lyosha [343]

Answer:  In constructing a box-and-whisker plot from a data set,  the minimum and maximum values are at the ends of the box.


Step-by-step explanation:

A box and whisker plot displays the five measures of data. The five measures summary is the minimum, first quartile, median, third quartile, and maximum. In a box plot, we draw a box from the first quartile to the third quartile.

Therefore, In constructing a box-and-whisker plot from a data set,  the minimum and maximum values are at the ends of the box.

Hence, A is the right option,

8 0
3 years ago
Please help me!!
Phoenix [80]

Answer:

=76

Step-by-step explanation:

24+(−9)(−4)+33−17

=24+36+33−17

=60+33−17

=93−17

=76

7 0
3 years ago
An uncooked gingerbread cookie is y centimeters long. After it is baked, the length of the
marusya05 [52]

Answer:

I think the answer is C

Step-by-step explanation:

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Find the indefinite integral by using the substitution x = 4 sec(θ). (Use C for the constant of integration.) x2 − 16 x d
guapka [62]

Answer:

\frac{x^2-16}{2} + 16ln\frac{4}{x}  +16C

Step-by-step explanation:

Given the indefinite integral \int\limits{\frac{x^2-16}{x} } \, dx, using the substitute

x = 4 sec(θ)...1

The integral can be calculated as thus;

First let us diffrentiate the substitute function with respect to θ

dx/dθ = 4secθtanθ

dx =  4secθtanθdθ... 2

Substituting equation 1 and 2 into the integral function we will have;

\int\limits{\frac{(4sec \theta)^2-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{16sec^2 \theta-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{(16(sec^2 \theta-1)}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\from \ trig \ identity,\  sec^2 \theta - 1 = tan^\theta\\\\\int\limits{\frac{16 tan^2 \theta}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\\int\limits 16 tan^3 \theta d \theta\\\\

Find the remaining solution in the attachment.

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3 years ago
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