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- We have given one irregular figure which is composed of semicircle and parallelogram
- <u>We have to find the total area of the given irregular figure .</u>
<u>We </u><u>have</u><u>, </u>
- Semicircle having diameter = 8 in.
- Therefore, R = 8/2 = 4 in.
- Parallelogram having base and height 10 in. and 6 in.
<u>We </u><u>know </u><u>that</u><u>, </u>
Area of semicircle
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
Area of parallelogram
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
Thus, The area of parallelogram is 60 in.
<h3><u>Therefore</u><u>, </u></h3>Area of the given figure
= Area of semicircle + Area of parallelogram
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
<u>When </u><u>round </u><u>off </u><u>to </u><u>nearest </u><u>Hundred </u>
Hence, The area of the given figure is 85.1 inches² .