True.
7/12 is greater than 4/12.
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Answer:
Positive gradient and the gradient is 3/2x
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
= x1 + x2/2 , y1 + y2/2
= 7+-1/2 , 1+(-1)/2
Midpoint = (3,0)
Answer:
1. 5x+3y, 2. 5h, 3. 5x+20-2x+8 --> 3x+28, 4. 2y-6+5x+5 --> 2y+5x-1
Step-by-step explanation: