Answer:
1) Maximum number of tables that can be kept in the dinning room is 10 tables
2)The maximum number of customers, given 6 people per table is 60 customers
Step-by-step explanation:
The parameters given are;
Distance between people seated at different tables = 6 ft
Dimension of table = 2 m by 1.5 m
Number of people at a table = 6 people
Dimension of dinning;
Width = 12 m
Length = 20 m
Dimension of entrance;
Width = 20/21*30 m
Length = 10 m
With 6 meters between tables and a table with of 1.5, we have for the arrangement in the question;
3 tables = 4.5 m
Distance between = 2 × 6 = 12
4.5 + 12 = 16 m (More room required)
With two tables, we have;
Width of tables = 2×1.5 = 3 m
Distance between = 6 m
Dining room width required = 3 + 6 = 9 m
Therefore, the maximum tables in each row = 2
Given that the dining room area extends to the entrance area, total length = 30 m.
With 4 tables we have;
Length = 4 × 2 + 6 × 3 = 26
While on the entrance side of the dinning room area which is 20 m, we have 3 tables;
Length = 3 × 2 + 6 × 2 = 18
Therefore, both arrangements are acceptable;
Just on entering by the right the length = 20/21×30 m
Therefore, with 3 tables will required number due to proximity wit the door and tables arranged along the right wall of the dinning
1) Maximum number of tables that can be kept in the dinning room = 4 + 3 + 3 = 10 tables
2)The maximum number of customers, given 6 people per table = 6×10 = 60 customers.
