Select all ratios equivalent to 1:2. is it 10:20. 7:14. 6:18.

If you invest $8,600 at a 3 95% simple annual interest rate, approximately how long will it take for you to have a toad of $21,0

Mariana [72]

Answer:

37 years.

Step-by-step explanation:

Interest = PRT/100 where P = Initial Amount, R = rate, T = the time.

So we have the equation:-

8600 + 8600*3.95 * T / 100 = 21000

8600 + 33970T / 100 = 21,000

8600 + 339.7T = 21000

339.7T = 21000 - 8600

T = (21000 - 8600) / 339.7

T = 36.5 years

5 0

3 years ago

During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str

Brilliant_brown [7]

Answer:

number of successes

$k = 235$

number of failure

$y = 265$

The criteria are met

A

The sample proportion is $\r p = 0.47$

B

$E =4.4 \%$

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from the true population proportion will not more than 4.4%

Ci

$r = 0.514 = 51.4 \%$

$v = 0.426 = 42.6 \%$

D

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

E

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

Yes our result would support the claim because

$\frac{1}{3 } \ of N < \frac{1}{2} (50\%) \ of \ N , \ Where\ N \ is \ the \ population\ size$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 500$

The sample proportion is $\r p = 0.47$

Generally the number of successes is mathematical represented as

$k = n * \r p$

substituting values

$k = 500 * 0.47$

$k = 235$

Generally the number of failure is mathematical represented as

$y = n * (1 -\r p )$

substituting values

$y = 500 * (1 - 0.47 )$

$y = 265$

for approximate normality for a confidence interval criteria to be satisfied

$np > 5 \ and \ n(1- p ) \ >5$

Given that the above is true for this survey then we can say that the criteria are met

Given that the confidence level is 95% then the level of confidence is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p (1- \r p}{n} }$

substituting values

$E = 1.96 * \sqrt{ \frac{0.47 (1- 0.47}{500} }$

$E = 0.044$

=> $E =4.4 \%$

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

substituting values

$0.47 - 0.044 < p < 0.47 + 0.044$

$0.426 < p < 0.514$

The upper limit of the 95% confidence interval is $r = 0.514 = 51.4 \%$

The lower limit of the 95% confidence interval is $v = 0.426 = 42.6 \%$

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

$\frac{1}{3 } < \frac{1}{2} (50\%)$

3 0

3 years ago

Jo is loading a freight elevator with 30-pound identical boxes. Jo weighs 180 pounds and his dolly cart for wheeling the boxes o

Firdavs [7]

Answer:

60 boxes

Step-by-step explanation:

180 pounds plus 20 pounds is 200 pounds, which means that the weight of the boxes can't be any more than 1800 pounds (2000 - 200 = 1800). Divide 1800 by 30 (weight of one box) and you'll get 60 boxes

6 0

3 years ago

An electrician is told to cut a piece of conduit to 11 and 3/4”. What would the decimal equivalent be?

Ahat [919]

Answer:

b) 11.75

Step-by-step explanation:

each quarter is equal to .25 so 3×.25 is .75

8 0

3 years ago

Numero multiplivado me de 28

miss Akunina [59]

The answer is 7 * 4
spanish: la respuesta es 7 por 4

7 0

3 years ago