1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//
Answer:
Y= 5
Step-by-step explanation:
14+13Y=20Y-21
-13y -13y
14=7y-21
+21 +21
35/7=7y/7
y=5
The general formula for the total surface area of a regular pyramid is T. S. A. =12pl+B where p represents the perimeter of the base, l the slant height and B the area of the base
To find the surface area of a regular triangular pyramid, we use the formula SA = A + (3/2)bh, where A = the area of the pyramid's base, b = the base of one of the faces, and h = height of one of the faces.
We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.
To find surface area for a rectangular prism, use the formula SA = 2ab + 2bc + 2ac, where a is the width, b is the height, and c is the length. If you're trying to find the surface area of a triangular prism, use the formula SA = 2a + ph, where a is the area of the triangle, p is the perimeter, and h is the height
Hope that was helpful.Thank you!!!
when the degree of the denominator is greater than that of the numerator, the only horizontal asymptote occurs at y = 0.
