Answer:
CPU is known as <u>Central</u><u> </u><u>Processing</u><u> </u><u>Unit</u><u>.</u>
Answer:
Question is incomplete.
Assuming the below info to complete the question
You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.
Detailed answer is written in explanation field.
Explanation:
We have to find the reachability using the directed graph G = (V, E)
In this V are boxes are considered to be non empty and it may contain key.
Edges E will have keys .
G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.
Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.
Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.
If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.
After first search from B we can start marking all other vertex of graph G.
So algorithm will be O ( V +E ) = O (n+m) time.
Answer:
False
Explanation:
namespaces can be nested. That is we can have a hierarchy of namespaces.
For examples suppose we have a namespace top. Within this we have another namespace first. At the next level we have a namespace called second. Then we have a class MyClass as a member of this namespace second. Then the complete description of the class will be as follows:
top::first::second::MyClass
Isn’t this for a online drivers test thing...? I believe you might want to figure this or on your own I’m sorry
Answer:
Web Accessibility Initiative
Explanation:
This is the group that creates disability standards online.