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uranmaximum [27]
3 years ago
11

In a Geometry class, Rosalie draws two circles on the coordinate grid as shown. She asks her students to prove that the two circ

les are similar.
Describe the transformation that maps circle C onto circle A?

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:huhhh

Step-by-step explanation:

Yh

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Kristin decides to spend at most $50 for a birthday dinner at a restaurant, including a 15% tip.,
Dmitry [639]
0.15x + x <(or equal to) 50
Where x is the meal's cost (no tip included)

50 - 15% = 42.5.
x >(or equal to) 42.50.

(nothing is copied content, I copy pasted a number into the right position, feel free to check it mods)
7 0
3 years ago
The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. Which equation models t
Zanzabum

Answer:  [H+] = 10^-7.2

Step-by-step explanation:

Given that the PH of the solution = 7.2

Using the formula pH = –log[H+]. To get the H+ concentration from the pH, raise both sides by the base of 10. Then we have

10^ -pH = H+. with pH of 7.2,

Thus the answer to this problem is

[H+] = 10^-7.2

8 0
3 years ago
Write an algebraic expression for the phrase the sum of g and 3
Paraphin [41]
The sum of g and 3. 

The sum of two values is added together. 

g+3

You would add g to 3 since it is their sum the statement is asking for.

I hope this helps!
~kaikers
3 0
3 years ago
Complete the stemplot for the following data. 33 46 23 38 33 31 52 20 20 22 34 30 44 28 33 39 33 37 58 32 43 35 26 24 30 22 57 4
kozerog [31]
50-60-79_%^*^%>?> ggg
4 0
2 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
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