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3 years ago

INTERMEDIATE LEVEL

Mathematics

1 answer:

vodomira [7]3 years ago

4 0

y = (1/2)x - 4

Step-by-step explanation:

The equation of the given line is

y = -2x + 13

The equation of the perpendicular line that we need must have a slope of 1/2 and passes through (2, -3) so the form should be

y = (1/2)x + b

To solve for b, use the point (2, -3)

-3 = (1/2)(2) + b ---> b = -4

Therefore, the equation that we need has the form

y = (1/2)x - 4

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1) If y = x3 + 2x and dx/ dt = 5, find dy/dt when x = 2. Give only the numerical answer. For example, if dy, dt = 3, type only 3

Semenov [28]

Answer:

a) 70

b) 10π ft²/ft

c) 0.24 ft/sec

Step-by-step explanation:

1) y = x³ + 2x

$\frac{dy}{dt}=\frac{d(x^3+2x)}{dt}$

$\frac{dy}{dt}$ = $3x^2\frac{dx}{dt}+2\frac{dx}{dt}$

at $\frac{dx}{dt}=5$ and x = 2

$\frac{dy}{dt}$ = $3(2)^2\times(5)+2\times(5)$

$\frac{dy}{dt}$ = 60 + 10 = 70

2) A = πr² ft²

$\frac{dA}{dr}=\frac{d(\pi r^2)}{dr}$

$\frac{dA}{dr}$ = 2(πr)

at r = 5 ft

$\frac{dA}{dr}$ = 2(π × 5) ft²/ft

$\frac{dA}{dr}$ = 10π ft²/ft

3) From Pythagoras theorem

Base² + Perpendicular² = Hypotenuse²

Thus,

B² + P² = H² .............(1)

here, H = length of the ladder

P is the height of the wall

B is the distance from the wall at bottom

B² + P² = 25² ...........(1)

at B = 20 ft

20² + P² = 25²

P² = 625 - 400

P = √225

P = 15 ft

differentiating (1) with respect to time, we get

$2B\frac{dB}{dt}+2P\frac{dP}{dt}=0$

at B = 20 ft, $\frac{dB}{dt} = 0.18$ and P = 15 ft

⇒ 2(20)(0.18) + $2(15)\frac{dP}{dt}$ = 0

$30\frac{dP}{dt}$ = - 7.2

$\frac{dP}{dt}$ = - 0.24 ft/sec (Here negative sign depicts the ladder slides down)

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Answer:

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