The answer is: g= 6y+8-9/y
Answer:
None of them are correct because the circumference formula is 2pir
There are a lot of ways but here are a couple of examples.
1. 1,2,3,4,5 - 1,2,4,5,3 - 1,4,5,3,2...... So on Hope this helps:)
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
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Look at the face of the pyramid facing you. The length of the base of this pyramid is 82 m; half of that is 41 m.
If you were to draw a straight vertical line through the vertex of the pyramid, the bottom of this line would be at the very center of the base and also be 41 in perpendicular distance from any of the edges of the base of this pyramid.
Let the height of the pyramid be y, as measured upward from the center of the base of the pyramid. This center is, as before, 41 m from any side of the pyramid base, a horiz. distance.
Then, tan 52 deg = y / 41 m, and so y = height of pyramid =
(41 m)(tan 52 deg) = (41 m) (1.28) = 52.48 m