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steposvetlana [31]
3 years ago
13

A number of 6 and a number

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

3

Step-by-step explanation:

maybe??? or 12 ........

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Question 9 of 25
tresset_1 [31]

Answer:

One approach to this problem is to obtain the graph for the given equation.

We need to find every intersection those functions have with the axis 'x' and 'y'

starting with g(x)

g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis

g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis

Lets do the same for f(x)

g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis

We dont need to find any other, since always y=x

By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
We use the properties of equality to rewrite equations and solve equations for a variable. These properties allow us to maintain
Katyanochek1 [597]
Help ASAP only right answers only no spam don’t answer if you don’t know

















Important usd
6 0
3 years ago
Least common denominator of 1/10 and 3/5
Alisiya [41]

Answer:

It's 10

Step-by-step explanation:

10 can be divided by five and 5 can also be divided by five and it's the least number that can be divided by five.

6 0
2 years ago
girls in the first grade account for one-third of the total strength of the class 3 girls are absent today. find the total stren
BabaBlast [244]
1/3x-3= 4;21 students
7 0
3 years ago
Joey invest $900 at 4% simple interest for 2 years but he wants to know how much money he will have after only 18 months. Determ
malfutka [58]
Well, bearing in mind that, a year has 12 months, so 18 months is really just 18/12 of a year, or 3/2 a year, then

\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$900\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to \frac{18}{12}\to &\frac{3}{2}
\end{cases}
\\\\\\
A=900\left( 1+0.04\cdot \frac{3}{2} \right)
4 0
3 years ago
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