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Sati [7]
2 years ago
13

The relationship between the number of hours a plumber works and the total work fee she charges is proportional her fee for 5 ho

urs of work is $350
Which of the following could be combination of values for the plumber work hours and total work fee she charges
Mathematics
1 answer:
VMariaS [17]2 years ago
8 0

Answer:Answer:

Step-by-step explanation:

Step-by-step explanation:Answer:

Step-by-step explanation:

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Question 3 is- B. 8 ounces

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3 years ago
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lakkis [162]

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Ask your teacher AKA me.

Step-by-step explanation:

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4 0
3 years ago
Jasmin, Quinn, and Maddy are rock climbing. Jasmin is 42 ½ feet below Quinn. Maddy is 67 ¾ feet above Jasmin. What is Maddy's po
ladessa [460]

Answer:

25\frac{1}{4} feet

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Step-by-step explanation:

Given

Maddy = 67\frac{3}{4} above Jasmin

Jasmin = 42\frac{1}{2} below Quinn

Required

Determine Maddy's position relative to Quinn's

From the given parameter, one can easily deduce that Quinn is in between Maddy and Jasmin (See attachment)

Using the attachment as a point of reference;

z = 67\frac{3}{4}

x = 42\frac{1}{2}

The relationship between x, y and z is

z = y + x

Make y the subject of formula

y = z - x

Substitute the values of z and x

y = 67\frac{3}{4} - 42\frac{1}{2}

Convert to improper fractions

y = \frac{271}{4} - \frac{85}{2}

Take LCM

y = \frac{271 - 170}{4}

y = \frac{101}{4}

y = 25\frac{1}{4}

<em>Hence; Maddy's position relative to Quinn's is </em>25\frac{1}{4}<em> feet</em>

8 0
3 years ago
Subtract 275000-30000
Varvara68 [4.7K]
Hi, it is 245,000 all you have to do is 70000-3000
5 0
3 years ago
Read 2 more answers
Help with Pre Calculus
marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. x(2x^2-x-15). So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\. So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}

4 0
2 years ago
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