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Nadya [2.5K]
3 years ago
13

Question 8 of 11

Mathematics
1 answer:
prisoha [69]3 years ago
5 0
By definition a triangle's third side must be larger than the difference of the other two sides (so in this case 10-10 = 0, so it must be larger than 0) and smaller than the sum (so 10+10 = 20 so it must be smaller than 20). Because this is not a specific type of triangle such as a right triangle, this is really the only rule that applies in this problem, so everything except E and F apply.
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2(3x+2)=2x-1+x solve
alina1380 [7]
First multiply and dstribute
a(b+c)=ab+ac
2(3x+2)=6x+4
6x+4=2x-1+x
add like terms
6x+4=3x-1
subtract 3x from both sides
3x+4=-1
subtract 4 from both sides
3x=-5
divide bothe sides by 3
x=-5/3
7 0
3 years ago
Find the area of the composite figure below.
pashok25 [27]

Answer: D is the correct answer.

8 0
3 years ago
The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of
emmasim [6.3K]

Answer:

The null hypothesis is: H_{0}: \mu = 100

The alternative hypothesis is: H_{a}: \mu > 100

Step-by-step explanation:

At the null hypothesis, we test if the mean is equal to a certain value.

At the alternate hypothesis, we test if the mean is less than, more than, or different from the value tested at the null hypothesis.

The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of 20 lb.

This means that the null hypothesis is: H_{0}: \mu = 100

Could it be that the average tuft strength is above 100 lb?

The world above means that the appropriate alternative hypothesis is: H_{a}: \mu > 100

3 0
3 years ago
HELP PLEASE laws of sines and/or cosines
Nastasia [14]

Answer:

A= 37 Degrees

C= 106 Degrees

i think this is what you need

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In the figure to the right, ABCD is a rectangle. Find the area of △ABC, if the area of △AOD is 10.
ehidna [41]
Assuming BOD and AOC are straight lines.

Area of the rectangle = 4 x ΔAOD
Area of the rectangle = 4 x 10
Area of the rectangle = 40 unit²

Area of ΔABC = 1/2 x 40 
Area of ΔABC = 20 unit²
5 0
3 years ago
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