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timofeeve [1]
3 years ago
13

Helllllllpppppp me plz

Mathematics
2 answers:
Genrish500 [490]3 years ago
5 0

Answer:

90 degrees

Step-by-step explanation:

liberstina [14]3 years ago
4 0

Answer:

x=103

Step-by-step explanation:

sum=(n-2)*180

sum=(6-2)*180

sum=4*180

sum=720

90+155+112+120+140+x=720

617+x=720

x=720-617

x=103

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What is the perimeter of the shape?
Serhud [2]

Answer:

20 cm

Step-by-step explanation:

Assuming that the side lengths you've written are the only side lengths of the shape, meaning it would be a trapezoid, all you do is add them up together.

3 + 5 + 5 + 7 = 20

3 0
3 years ago
Read 2 more answers
Which of the following is the least? A. 0.105 B. 0.501 C. 0.015 D. 0.15
Naddika [18.5K]
C is the least that is beause it is .015  which is smaller than 0.15
8 0
3 years ago
Is AB and CD parallel? Why/why not
adelina 88 [10]

Step-by-step explanation:

AB and CD is not parallel because co-interior sum is 180 and another reason is that parallel sign isn't given.

4 0
2 years ago
How do I solve this question?
Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given  [ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

using algebraic formula (a^m)^n= a^{mn}

now

2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}

now equating 'x' powers, we get

x^{mn} = x^{6}

mn=6 ....(1)

now

y^{2m} = y^{4}

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

(2 x^{3} y^2)^2 = 4 x^6 y ^4\\

4 x^6 y^4 = 4 x^6 y^4

both are equating so m= 2 and n=3

4 0
3 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
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