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andrezito [222]
3 years ago
14

Write (p^2)^3 without exponents

Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

p^6

Step-by-step explanation:

We are using rule power to a power. x^2^3 = x^(2*3)

p^6

Hope this helps plz hit the crown :D

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If you solve the inequality 2x < 14, the solution set is x < 7. Graph x < 7 on a number line. Which one of the listed v
Crazy boy [7]

Answer:

its D) x = -8 is correct

All the values less than 7 are included in the number line. The graph on number line is shown in figure attached. In the options given, all values in Option A, B and C are greater than 7 so these cannot be included.

-Hops

5 0
3 years ago
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What value of x gives y= -2 ?
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The value of x = 0 which is none
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3 years ago
The bill for five hamburgers and four salads is $9.50. The bill for four hamburgers and five salads is $10.30. What would be the
Sunny_sXe [5.5K]

Answer: the bill for a hamburger is $0.7

the bill for a salad is $1.5

Step-by-step explanation:

Let x represent the bill for a hamburger.

Let y represent the bill for a salad.

The bill for five hamburgers and four salads is $9.50. This means that

5x + 4y = 9.5- - - - - - - - - - - - - - 1

The bill for four hamburgers and five salads is $10.30. This means that

4x + 5y = 10.3 - - - - - - - - - - - - - -2

Multiplying equation 1 by 4 and equation 2 by 5, it becomes

20x + 16y = 38

20x + 25y = 51.5

Subtracting, it becomes

- 9y = - 13.5

y = - 13.5/ - 9

y = 1.5

Substituting y = 1.5 into equation 1, it becomes

5x + 4(1.5) = 9.5

5x + 6 = 9.5

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7 0
3 years ago
+
viva [34]

Answer:

(x - 1) (x + 2) (x + 4)

Step-by-step explanation:

Factor the following:

x^3 + 5 x^2 + 2 x - 8

The possible rational roots of x^3 + 5 x^2 + 2 x - 8 are x = ± 1, x = ± 2, x = ± 4, x = ± 8. Of these, x = 1, x = -2 and x = -4 are roots. This gives x - 1, x + 2 and x + 4 as all factors:

Answer: (x - 1) (x + 2) (x + 4)

6 0
3 years ago
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In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to dou
Alex777 [14]

Answer:

It would take 19 hours and 36 minutes until there are 1040 bacteria present.

Step-by-step explanation:

Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:

610X = 1040

X = 1040/610

X = 1.7049

2 = 23

1.7049 = X

1.7049 x 23/2 = X

39.2131 / 2 = X

19.6 = X

100 = 60

60 = X

60 x 60/100 = X

36 = X

Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.

5 0
3 years ago
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