All categories

2 years ago

Write (p^2)^3 without exponents

Mathematics

1 answer:

Vilka [71]2 years ago

5 0

Answer:

p^6

Step-by-step explanation:

We are using rule power to a power. x^2^3 = x^(2*3)

p^6

Hope this helps plz hit the crown :D

You might be interested in

An experience bricklayer can construct a small wall in 3 hours. An apprentice can complete the job in 5 hours. Find how long it

Over [174]

Answer:

Step-by-step explanation:

If the bricklayer can construct the wall in its entirety in 3 hours, then he can get 1/3 of the job done in an hour.

If the apprentice can get the whole job done in 5 hours, then he can get 1/5 of the job done in an hour. If they both work together on said job, the equation is

$\frac{1}{3}+\frac{1}{5}=\frac{1}{x}$ and now we solve for x. Multiply everything by the LCM to get rid of the fractions. That would be 15x:

$15x(\frac{1}{3}+\frac{1}{5}=\frac{1}{x})$ and doing that gives us

5x + 3x = 15 and

8x = 15 so

x = 1.875 hours which is 1 7/8 hours which is also 1 hour and 52 1/2 minutes.

3 0

2 years ago

The number of employees per department are normally distributed with a population standard deviation of 198 employees and an unk

cricket20 [7]

Answer:

EBM = +-54.126

Step-by-step explanation:

In this question we have confidence interval to be 80%

The formula to solve this is in the attachment.

Bar X = 1460

Z-alpha/2 = 1.282

Sd = standard deviation = 198 employees

n = 22 departments

After we have inserted all values in to the formula we have:

1460 +-(1.282*198/√22)

= 1460+-(54.12604)

= (1405.87, 1514.126)

The error bounded mean EBM

= +-z-alpha/2 x (sd/√n)

= 1.282 x 198/√22

= 1.282 x 42.22

EBM = +-54.126

6 0

2 years ago

The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho

lyudmila [28]

Answer:

The solution to f(x) = s(x) is x = 2012.

Explanation:

Rewrite the table and the choices for better understanding:

Enrollment at a Technical School

Year (x) First Year f(x) Second Year s(x)

2009 785 756

2010 740 785

2011 690 710

2012 732 732

2013 781 755

Which of the following statements is true based on the data in the table?

The solution to f(x) = s(x) is x = 2012.

The solution to f(x) = s(x) is x = 732.

The solution to f(x) = s(x) is x = 2011.

The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012, x = 2012.

Thus, the correct choice is the third one: