The options are not provided, but method is stated below
Answer:
Quadratic equation ax2 - 6x + c = 0
options would be given for a and c
- substitute a and c
- check for Discriminant
-
- 36 -4ac
These conditions will fetch us the result required among the options.
Note : the 
sign will give us the result for Two real unequal solutions and two real equal solutions. If we only need Real unequal solutions we only use > sign instead of
An exponential parent function is the option C. f(x)= 
, from the given options.
What do you mean by exponential parent function?
The formula for their parent function is y = 
, where b is any non zero constant. Below is a graph of the parent function, y = 
, which demonstrates that it will never equal 0. And at y = 1 when x = 0, y crosses the y-axis.
According to options in the given question,
We have the option below in the given question:
A. f(x) = 2^x – 3 
B. f(x) = 2^x + 2 
C. f(x) = 2^x 
D. f(x) = 2^x + 1/3
We know from the above definition that the option C. is the right answer to the given question.
Therefore, the exponential parent function is f(x)= .
To learn more about exponential parent function, visit:
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This basically means that you have to multiply the x and y values by 3. So 2 time 3 is 6. And -7 times 3 is -21. So the new coordinations are (6, -21)
Hope this helped and pls mark as brainliest!
~ Luna
Answer:
A. x≥4 ( red on 4)
B. x≤4 ( red on 4)
C. x>4 (blue on 4)
D. x<4 (blue on 4)
Step-by-step explanation:
illustrated
A. x≥4 ( red on 4)
B. x≤4 ( red on 4)
C. x>4 (blue on 4)
D. x<4 (blue on 4)
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
