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snow_tiger [21]
3 years ago
8

Help I need an explanation

Mathematics
2 answers:
shepuryov [24]3 years ago
4 0

Answer:

Step-by-step explanation:

X =75

stellarik [79]3 years ago
4 0

Answer:

180° - 105 = 75°i.e angle EFB (sum of angle in st.line)

Step-by-step explanation:

X°= angle EFB ( being corresponding angle)

Hence the value of x is 75

You might be interested in
What is 8x - ( 3x + 7 )= 23
slavikrds [6]
8x - 3x - 7 = 23
5x - 7 = 23
5x = 30
x = 30/5 = 6
3 0
3 years ago
Elmer started out with$103 in his bank account .he spent $4 per week at the cafeteria for snacks.what is the slope (m) for this
pochemuha

Answer:

The equation is y=-4x+103

The slope is m=-4

Step-by-step explanation:

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

y is the amount left in the saving account

x is the number of weeks

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value

In this problem we have

The slope is equal to

m=-\$4\ per\ week --> is negative because is a decreasing function

The y-intercept or initial value is

b=\$103

substitute

y=-4x+103

5 0
4 years ago
) Factorise<br> a2 + ab + a<br> Answer
mr_godi [17]

Answer:

Step-by-step explanation:

a^2+ab+a

a(a+b+1)

5 0
3 years ago
Read 2 more answers
REALLY APPRECIATE YOUR HELP<br><br>Given log x = 3 and log y = 2, prove that x^2 -7xy =3000y​​
anyanavicka [17]

Answer:

if \:  log(x )  = 3 \\  log_{10}(x)  = 3 \\   {10}^{3}  = x \\ therfore \to \:  \boxed{x =  {10}^{3} } \\ \\  if \:  log(y )  = 2 \\  log_{10}(y)  = 2 \\   {10}^{2}  = y \\ therfore \to \:  \boxed{y=  {10}^{2} }

Step-by-step explanation:

x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2}  = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{5} )   \\  {10}^{6}  = 300000 + 700000 \\   \boxed{{10}^{6}  = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}

♨Rage♨

3 0
3 years ago
Select all intervals in which the function P(t) is decreasing
Irina-Kira [14]

Answer:

we conclude that the intervals in which the function P(t) is decreasing are:

  • x < 1
  • 3 < x < 4

Step-by-step explanation:

At x< 1, the function P(t) is decreasing

  • A function p is an increasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>x
  • A function p is a decreasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>x

From the figure, it is clear that the function seems to be increasing

from (1, 3) and then 4 to onwards.

But it is clear that the function seems to be decreasing from the x < 1 and from the interval (3, 4).

Therefore, we conclude that the intervals in which the function P(t) is decreasing are:

  • x < 1
  • 3 < x < 4
6 0
3 years ago
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