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Neporo4naja [7]
3 years ago
13

7TH GRADE MATH IF YOU HELP ILL GIVE BRANLIEST AND 10 POINT//PROBABILITY

Mathematics
2 answers:
tigry1 [53]3 years ago
8 0

1) 20%

2) Assuming that on the spinner with color, every section has an equal share, then the probability of landing on orange is \frac{1}{5} or 20%. This is because, the orange section is one of the five equal sections, or \frac{1}{5} or the spinner. \frac{1}{5} in decimal form is 0.2, to convert to a percent, multiply by 100. Hence one gets, 20%.

3) 40

4) There are 5 sections on the spinner with color, hence 5 possible outcomes when one spins the spinner. On the black and white spinner, there are 8 sections, hence 8 possible outcomes when one spins the spinner. To find the total number of outcomes resulting from the two events, one must multiply the total outcomes from one event by the total outcome of the other event. When one does this, they get that there are 40 possible events.

Ierofanga [76]3 years ago
4 0

Answer:

1. 1 in 5

2. There are 5 colors it could land on, and orange is one of them.

3. 40 different combinations

4. There are 5 colors with 8 corresponding numbers. 5x8=40

Step-by-step explanation:

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7

Step-by-step explanation:

its the middle number between the first and last

hope this helps!

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Royce has $15 with him and spends $12 to buy his favorite comics. He has $3 left, which he deposits in the bank. Which number wi
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The value 3 will be entered. It's a positive value to indicate he is not in debt of any kind. 
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2 years ago
A recipe has a ratio of 2 cups of dark soy sauce to 3 cups of light soy sauce. How many cups
Tanya [424]

Answer:

2/3 cup

Step-by-step explanation:

2:3

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4 0
2 years ago
Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17
V125BC [204]

Looks like the system is

x + 4y - z = -14

5x + 6y + 3z = 4

-2x + 7y + 2z = -17

or in matrix form,

\mathbf{Ax} = \mathbf b \iff \begin{bmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -14 \\ 4 \\ -17 \end{bmatrix}

Cramer's rule says that

x_i = \dfrac{\det \mathbf A_i}{\det \mathbf A}

where x_i is the solution for i-th variable, and \mathbf A_i is a modified version of \mathbf A with its i-th column replaced by \mathbf b.

We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

\det \mathbf A = \begin{vmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{vmatrix}

\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}

\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))

\det\mathbf A = 12 - 21 - 40 - 24 - 35 - 12 = -120

The modified matrices and their determinants are

\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240

\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360

\mathbf A_3 = \begin{bmatrix} 1 & 4 & -14 \\ 5 & 6 & 4 \\ -2 & 7 & -17 \end{bmatrix} \implies \det\mathbf A_3 = -480

Then by Cramer's rule, the solution to the system is

x = \dfrac{-240}{-120} \implies \boxed{x = 2}

y = \dfrac{360}{-120} \implies \boxed{y = -3}

z = \dfrac{-480}{-120} \implies \boxed{z = 4}

5 0
2 years ago
What do conjecture means
jeka94

Answer:

an opinion or conclusion formed on the basis of incomplete information.

Step-by-step explanation:

comment how it helps

5 0
3 years ago
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