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velikii [3]
3 years ago
11

Someone help please

Mathematics
2 answers:
goblinko [34]3 years ago
6 0

Answer:

12/35

Step-by-step explanation:

(6/7)*(2/5)=(12/35)

Sav [38]3 years ago
4 0

Answer:

12/35 don't know if you haft to simplify tho

Step-by-step explanation:

6/7×2/5=12/25

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Review the graph.
lisabon 2012 [21]

Answer: A, Magnitude of 8 and direction angle equal to 0°

Step-by-step explanation:

Since vector u is only a straight line, there will be no angle, which means that answers B and D are automatically wrong.

Now, we’re going to use the distance formula to find the component form of vector u

\sqrt{(6-(-2)^2+(3-3)^2}\\\\\sqrt{(8)^2+(0)^2}

Now we found the new coordinate, which is (8,0), and it is being extended from the origin with the same angle of 0°

Using the formula from above, we can find the magnitude of vector u

\sqrt{(8)^2+(0)^2} \\\\\sqrt{64+0}\\\\\sqrt{64}\\\\8

Hope I explained it well and hopefully this helps!

7 0
3 years ago
Read 2 more answers
Question 3 (1 point) If the following is a rhombus, find the missing measures. Find PQ. PQ=​
Svetllana [295]

Answer:

Step-by-step explanation:

PQ*PQ=PQ²=(5x+16)²=25x²+160x+256

8 0
3 years ago
How to solve x^2 + 3x + xk + 3k
zalisa [80]
Simplified:
kx + x² + 3x + 3k
4 0
3 years ago
Helpppppp!!!! Pleaseee
velikii [3]

Answer:

-512

Step-by-step Explanation

5 0
2 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
a_sh-v [17]
For AC:
 AC= root((a-0)^2 + (b-0)^2)
 AC= root((a)^2 + (b)^2)
 For BD:
 AC= root((a-0)^2 + (0-b)^2)
 AC= root((a)^2 + (-b)^2)
 AC= root((a)^2 + (b)^2)

 Therefore,
 AC=BD
8 0
3 years ago
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