The acceleration of the pendulum mass D is; r"_d = [x''(t) + lθ'' cos θ - lθ'² sin θ]i - l[θ'' sin θ - θ'² cos θ]j
<h3>What is Kinematics of particles?</h3>
Kinematics is the study of the geometry of motion of particles, rigid bodies, etc., disregarding the forces associated with these motions. However, Kinematics of a particle is the motion of a point in space.
From the sample problem, we can solve it using the (x, y, z) coordinate system to get;
r_c = x(t) i
r_d = [x(t) + l sin θ]i + l cos θ j
Finding the first derivative of r_d gives velocity as;
r'_d = [x'(t) + lθ' cos θ]i - lθ' sin θ j
Taking the second derivative of r_d gives the acceleration as;
r"_d = [x''(t) + lθ'' cos θ - lθ'² sin θ]i - l[θ'' sin θ - θ'² cos θ]j
A sample problem of kinematics of particles is;
A block C slides along the horizontal rod, while a pendulum attached to the block can swing in the vertical plane. Find the acceleration of
the pendulum mass D.
Read more about Kinematics of Particles at; brainly.com/question/26269548
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The value of kb of cyclohexane in the given question is; kb = 2.82 °C/m
<h3>Understanding Molality of a Solution</h3>
Molality of solution = (Number of moles of C₆H₄Cl₂)/(Mass of Cyclohexane)
Now;
Number of moles of C₆H₄Cl₂ = Mass/molar mass = 2g/147 g/mol
Number of moles of C₆H₄Cl₂ = 0.0136 mol
Molality of solution = 0.0136/(22.5 * 10⁻³ kg)
Molality of solution = 0.6 m
Now, to find kb for cyclohexane, we will use the formula;
T_b(solution) - T_b(solvent) = kb × molality of solution
Thus;
82.39 - 70 = kb * 0.6
kb = (82.39 - 70)/0.6
kb = 2.82 °C/m
Read more about Molality of Solution at; brainly.com/question/10278982
Answer:
1500 N
Explanation:
Weight = mg = 150 kg * 10 m/s^2
Weight = 1500 N
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