a. A bag contains 7 b l u e marbles, 10 g r e e n marbles, and 5 r e d marbles. If a marble is drawn from the bag, replaced, and
another marble is drawn, what is the probability of drawing first a b l u e marble and then a r e d marble
1 answer:
7 + 10 + 5 = 22 total marbles.
Picking a blue one first would be 7 blue/22 total = 7/22
Picking a red one would be 5 red / 22 total = 5/22
Picking blue first and then red = 7/22 x 5/22 = 35/484
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Scholar #2 is correct. You take 15=-3m-18+5m-7 and combie like terms. Which will leave you with 15=2m-25. You will simplify from there, getting 20=m.
8/12 in simplest form is 2/3.
Answer:
39/20 = 1.95
That's my simplified answer
39/20 = 1 19/20
Will this help?
Step-by-step explanation:
1.7a + 0.3a = 0.8;
(1.7 + 0.3)a = 0.8;
2 x a = 0.8;
a = 0.8 ÷2;
a = 0.4;
