Answer:
16. D
17. 5^-1 · 5^-1 and 25^-1
8^0 · 8^3 and 8^3
Step-by-step explanation:
When you multiply two same numbers with exponents, just think of it as adding up exponents.
When you divide two same numbers with exponents, just think of it as subtracting exponents.
If a parenthesis has an exponent outside, then every exponent inside the parenthesis will be multiplied by that outside parenthesis.
(5^-1)^-2 · 5^3 ÷ 5^7
5^2 · 5^3 ÷ 5^7
5^5 ÷ 5^7
5^-2
When exponents are negative, you have to flip them or put them on the other side
5^-2 = 1/5^2 = 1/25
Let's try to find the equivalent pairs
6^7 ÷ 6^-2 = 6^5
6^9 = 6^5 Not equivalent
(6^3)^0 = 6
6^0 = 1 (Any number with a zero exponent is always 1)
1 = 6 Not equivalent
5^-1 · 5^-1 = 25^-1
5^-2 = 25^-1
Flip em
1/5^2 = 1/25
1/25 = 1/25 Equivalent
8^0 · 8^3 = 8^3
8^3 = 8^3 Equivalent
4^-3 ÷ 4^2 = 4^5
4^-5 = 4^5 Not equivalent
I think maybe c but I’m not sure!
Answer:
<h2>The function is</h2><h2>

</h2>
Step-by-step explanation:
At t = 0 the difference is 100 degree celsius.
After one second the temperature difference will be
= 
After two second, the difference will be 
Hence, it can be written that,
= 