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3 years ago

División del núcleo de la mitosis

Biology

1 answer:

Natali [406]3 years ago

6 0

Answer:

La cariocinesis (del griego cario = núcleo y cinesis = movimiento), mitosis astral o mitosis anfiastral, es la división del núcleo celular. Consiste en la primera fase de la mitosis, que es el proceso por el cual el material genético de una célula madre se distribuye de manera idéntica entre dos células hijas.

Explanation:

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Help me please. Need help in science i don't understand.

Kaylis [27]

The decay of Francium produces radium-223 (Ra-223) through a beta decay or into astatine-219 through an alpha decay. The atomic number of Francium is 87, and that of Astatine is 85.

<h3>What is beta decay?</h3>

Beta decay is a type of radioactive decay in which a beta ray is emitted from the nucleus of an atom. During the beta decay, a proton in the nucleus is transformed into a neutron and vice versa which results into change in the number of proton in the nucleus. If a proton is converted to a neutron, then it is said to be β+ decay. And, if a neutron is converted to a proton, then it is said to be β– decay.

In this reaction, an atom of Francium (Fr-223) is undergoing a beta decay to produce radium (Ra-88) by the conversion of a neutron into a proton.

Learn more about decay here:

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6 0

1 year ago

A scientist wants to determine whether a mutant phenotype is due to the loss of gene C or gene D, which are both deleted in a mu

klio [65]

Answer:

a transgenic copy of the gene C is sufficient to restore normal eye development

Explanation:

In genetics, there are diverse approaches to determining a gene's function. For example, it is possible to use a complementation test to determine loss-of-function recessive mutations when it is unknown if such mutations fall in the same or in different genes. Similarly to the generation of loss-of-function phenotypes, it is possible to insert a gene and thus produce a gain-of-function mutation that restores normal gene function (i.e., to restore the wild phenotype). Moreover, transgenic organisms refer to genetic engineering techniques by which any foreign or modified gene is inserted in the genome of an organism, which can also be used to study gene function. In this case, the restoration of the normal phenotype (wild-type eyes) is associated with the expression of the transgenic gene C, thereby evidencing that the gene C is required for normal eye development. In the last years, transgenic models have shed light on developmental pathways and on gene function.

7 0

3 years ago

Write a clam about how does a Gramma Ray has the most energy

Akimi4 [234]

Answer:

Yuh

Explanation:

Because a gamma ray has higher frequency waves, and those high frequency waves contain the most energy. They have short wavelengths but high frequencies, therefore, because of those high frequencies, that is why it contains the most energy among them.

8 0

3 years ago

Read 2 more answers

How do sea anemone catch prey?

V125BC [204]

Answer:

Tentacles have specialised stinging cells called nematocysts. They use these to immobilise their prey so that the tentacles are then able to move the food into the mouth.

Explanation:

6 0

3 years ago

If the a and b loci are 20 m.u. apart in humans and an A B/ a b woman mates with an a b/ a b man, what is the probability that t

Elanso [62]

Answer:

The probability of having a Ab/ab child is 10%

Explanation:

The genes A/a and B/b are linked and 20 m.u. apart.

The parental cross is:

Gametes:

The man only produces 1 type of gametes, so the probability of him producing an ab gamete is 1.

The woman produces 4: two parental (AB and ab) and two recombinant (Ab, aB).

Man: ab

Woman: AB, ab, Ab, aB

The formula to relate genetic distance with recombination frequency is:

Genetic Distance (m.u.)= Recombination Frequency X 100.

Replacing the data in the formula, we have:

20 m.u. / 100 = Recombination Frequency

0.2 = Recombination Frequency

Because the Recombination Frequency is 0.2, the woman will generate recombinant gametes 20% of times, and parental gametes the other 80%. Each recombinant gamete will appear in 10% of the cases, and each parental gamete will appear in 40% of the cases.

The probailities for each possible genotype of the progeny resulting from that cross will be:

Parental: AB/ab 40%

Parental: ab/ab 40%

Recombinant: Ab/ab 10%

Recombinant: aB/ab 10%

7 0

4 years ago

División del núcleo de la mitosis​

División del núcleo de la mitosis