To find the maximum height you need to find the vertex:(h,k)
Your equation is in vertex form a(x-h)+k and the vertex is (h,k) where k is the maximum height and the h is the distance it went to reach the maximum height.
k=6 so the kangaroo's maximum height is 6 feet.
To find how long is the kangaroo's jump, take a look at the graph. You will notice that the parabola ends at the distance the kangaroo jumped. You will also see that it is the one of the x-intercepts.
-.03(x-14)^2+6=0
-.03(x-14)^2+6-6=0-6
-.03(x-14)^2=-6
-.03/-.03(x-14)=-6/-.03
(x-14)^2=200
[(x-14)^2]^.5=200^.5
x-14=(200)^.5
x-14+14=(200)^.5+14
x≈28.14 feet
The kangaroo jumped a distance of 28.14 feet.
You will notice that the square root of a number gives you two solutions a positive and a negative one. The other solution is -.14, which we know distance is not negative so we do not use that solution. Also, I used the ^.5 instead of using the square root. It is the same.
Answer:
Step-by-step explanation:
7) Area = 615.75 sq. km
πr² = 615.75
3.14*r² = 615.75
r² = 615.75/3.14 = 196
r = √196
r = 14 km
8) circumference = 15.71 yards
πd = 15.71
3.14*d = 15.71
d = 15.71/3.14 = 5 yards
9)Area = 415.48 sq.inches
πr² = 415.48
3.14*r² = 415.48
r² = 415.48/3.14 = 132.31
r = √132.31
r = 11.5 inches
diameter = 11.5*2 = 23 inches