1. Y = 10x
2. Y = 100 + 30x
3. Y = 50 + 1x
5. Y = 15 + .12x
Answer: Angle OZP= 62 Angle PZQ=63
(4r+2)+(5r-12)=125
9r-10=125
9r=135
r=15
Angle OZP Angle PZQ
4(15)+2 5(15)-12
62 63
Answer:
the largest angle of the field is 149⁰
Step-by-step explanation:
Given;
perimeter of the triangular filed, P = 120 m
length of two known sides, a and b = 21 m and 40 m respectively
The length of the third side is calculated as follows;
a + b + c = P
21 m + 40 m + c = 120 m
61 m + c = 120 m
c = 120 m - 61 m
c = 59 m
B
↓ ↓
↓ ↓
↓ ↓
A → → → → → → → → → → → C
Consider ABC as the triangular field;
Angle A is calculated by applying cosine rule;

Angle B is calculated as follows;

Angle C is calculated as follows;

Therefore, the largest angle of the field is 149⁰.
You put the whole number on top of 1, it doesnt change its value. then you simplify across like in a butterfly only if needed then you multiply across from left to right.
Increase = 14
Total =50
Percentage increase = 14/50 x 100 = 28%