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Bad White [126]
3 years ago
6

I need the answer fast pls

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0
1/8 is the mode. It appears most often
aev [14]3 years ago
3 0

Answer:

Option A, 1/8 pound would be the correct answer

Step-by-step explanation:

Since mode of the data is the number in the data that occurs the most, if noticed 1/8 occurs 4 times in the data set given and hence is the mode of the data set

Hope this helps!

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What is the area of the figure below?
rusak2 [61]

Answer:

B) 43in^2

Step-by-step explanation:

I did the work but I'm very bad at explaining it. What I can say is area of 2 little square is 9 so 9x2=18 Then area of big square is 25 so 25+18= 43

4 0
3 years ago
I need help plez and thanks
Brilliant_brown [7]
He has a total of $58.19.
1 day = $2.74

58.19/2.74 
21.24

You can't have 21.2 days, so you need to round down to 21.

Jim can buy lunch for 21 days before he runs out of money on his account.
3 0
3 years ago
Read 2 more answers
If one side of a square measures 6 units,<br> what is its area?
aniked [119]

Answer: Area=36

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
PLEASE HELP ME!!!!!!!
Sidana [21]
He has come from the hole in the roof because the text states that he did not come from a door, a window, or a chimney, and that is the only answer that was left.
4 0
3 years ago
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