<h3> (8) An aeroplane takes off from Dubai located in the +4 time zone at 13:00. It arrives in Manila in Philippines, located in the +8 time zone at 20:00.</h3>
- (1) Find the time in Manila when the aeroplane departsfrom Dubai.
- (ii) Find the time duration of the flight.
- (iii) What is the time in Dubai when the aeroplane arrives in Manila?
- (i)17.00
- (ii)3 hours
- (iii) 16.00
<h3>Dubai located +4 zone, takes off at 13.00,</h3>
∴Hence, at standard it is 13.00-4 =99.00 STD talk
off reached at Manila +8 Zone at 20.00
∴Hence at standard & 2000 -8
reached.⇒ 12.00 STD
- Hence time of flight was = 3 hours.
(i) Time at Manila, whicle Plane de parts
12-3+8 ⇒9+8 → 17.00
(ii) duration = 3 hours.
(iii) in dubai 13.00 + 3 = 16,00
_____________________
Ans
i)17.0.0 (ii) 3 hours (iii) 16.00
________________________
♕ hence we done:) xD
It's 27 because two negatives cancels each other out.
Answer:
it would be 25p + 48b = # of Straws
Step-by-step explanation:
<span>Answer:</span><span>
<span>B) The maximum height is 11.3 ft and it reaches this height at 0.72
seconds.
</span>Explanation:
Part (a) : getting the
time taken to reach maximum height:
The given equation is:
h = -16t² + V0*t + h0
We are given that:
Initial velocity (V0) =23 ft/sec
Initial height (h0) = 3 ft
The equation now becomes:
h = -16t² + 23t + 3
For maximum height:
dh / dt = zero
This means that:
-16(2) t + 23 = 0
-32t + 23 = 0
32t = 23
t = 0.71875 sec which is approximately 0.72 seconds
Part (b): getting the
maximum height:
The equation given to get the height is:
h = -16t² + V0*t + h0
We are given that:
Initial velocity (V0) =23 ft/sec
Initial height (h0) = 3 ft
We have calculated that:
time taken to reach maximum height = 0.72 sec
Substitute with the givens in the equation to get the maximum
height as follows:
h = -16t² + V0*t + h0
h = -16(0.72)² + 23(0.72) + 3
h = 11.2656 ft which is approximately 11.3 ft
Hope this helps :)</span>
