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3 years ago

1. list the pairs of alternate exterior angles

Mathematics

1 answer:

Sveta_85 [38]3 years ago

3 0

Answer:

1. m<a and m<h, m<e and m<d

2.m<a and m<c, m<b and m<d, m<e and m<g, m<f and m<h

3. m<a= 112

m<c=112

m<f=112

m<h=112

m<b=68

m<d=68

m<e=68

m<g=68

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Does the table show a direct proportional relationship? If so, what is the constant of proportionality?

lesantik [10]

Answer:

C. Yes, 3.5.

Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality ( $k$ ) is described by the following expression:

$k = \frac{y}{x}$ (1)

Where:

$x$ - Input.

$y$ - Output.

If we know that $(x_{1}, y_{1}) = (13, 45.5)$ , $(x_{2}, y_{2}) = (14, 49)$ and $(x_{3}, y_{3}) = (15, 52.5)$ , then the constants of proportionalities of each ordered pair are, respectively:

$k_{1} = \frac{y_{1}}{x_{1}}$

$k_{1} = \frac{45.5}{13}$

$k_{1} = \frac{7}{2}$

$k_{2} = \frac{y_2}{x_2}$

$k_{2} = \frac{49}{14}$

$k_{2} = \frac{7}{2}$

$k_{3} = \frac{y_{3}}{x_{3}}$

$k_{3} = \frac{52.5}{15}$

$k_{3} = \frac{7}{2}$

Since $k_{1} = k_{2} = k_{3}$ , the constant of proportionality is 3.5.

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3 years ago

Simplify 10 + 4(x + 1) + 5

Levart [38]

Distribute
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Combine like terms
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Help me plz with this answer

Lesechka [4]

$52.50 / 42 = 1.25
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A five card hand is dealt. What is the probability that the hand is all diamonds?

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Two out of five Would be my answer

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how is building a triangle with different side lengths given different than building a quadrilateral with given side lengths?

Mariana [72]

Answer:

there can only be one possibility for a triangle when given the lengths of all the sides but for a quadrilateral the measure of the angles could differ depending on the person building the,. this is because triangles are more stable than quadrilaterals meaning that their side lengths follow a lot more rules than quadrilaterals do, for example the length of the side lengths can indicate whether or not that triangle is an acute, obtuse, or right triangle, and this is also evident by considering that you can use the SSS theorem to indicate two triangles are congruent, but for quadrilaterals you cant do that

Step-by-step explanation:

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4 years ago