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ICE Princess25 [194]
2 years ago
13

1. list the pairs of alternate exterior angles

Mathematics
1 answer:
Sveta_85 [38]2 years ago
3 0

Answer:

1. m<a and m<h, m<e and m<d

2.m<a and m<c, m<b and m<d, m<e and m<g, m<f and m<h

3. m<a= 112

m<c=112

m<f=112

m<h=112

m<b=68

m<d=68

m<e=68

m<g=68

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How many solutions does 2x+ 2x+ 2=4+2x have
yuradex [85]
Let's see!
2x + 2x + 2 = 4 + 2x\\ 4x + 2 = 4 + 2x\\ 4x - 2x + 2 = 4 + 2x - 2x\\ 2x + 2 = 4\\ 2x + 2 - 2 = 4 - 2\\ 2x + 0 = 2\\ 2x = 2\\ 2x/2 = 2/2\\ x = 1\\
The answer is B
3 0
3 years ago
The table below shows that 1 day equals 24 hours. Notice that 12 hours is one-half of that. Use the table to help you determine
djverab [1.8K]

Answer:

There are 1.25 days in 30 hours or 1 1/4 days in 30 hours

Step-by-step explanation:

As we know one day is 24 hours. So if we divide 30 hours by 24 hours (or one whole day) then we get 1.25 days or also known as 1 1/4 days

6 0
3 years ago
For her book club, Sharon reads for 45 minutes each day. Write an expression for the number of hours she reads in d days?
VMariaS [17]
H=45d h stands for hours and 45d means 45 minutes per day
3 0
3 years ago
Read 2 more answers
Professor Vinculum investigated the migration season of the Bulbul bird from their natural wetlands to a warmer climate. He foun
coldgirl [10]

The population of the Bulbul birds at the start of the migration season is 1800.

<h3>Exponential function</h3>

An exponential function is given by:

y = abˣ

Let y, x are variables, a is the initial value and b is the multiplication factor.

Let P be the population of the bird t days since the start of the migration season.

P=1350+400(1.25)^{-t}\\\\At\ the\ start\ of\ the\ season(t=0):\\\\P=1350+400(1.25)^{-0}\\\\P=1350+450=1800

The population of the Bulbul birds at the start of the migration season is 1800.

Find out more on Exponential function at: brainly.com/question/12940982

8 0
2 years ago
1. tan a = cot(a + 10°)
Temka [501]

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

7 0
2 years ago
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