3(5+4b)
3×5=15+3×4=12b=
15+12b
the first one is left and the second one is up
Answer: B = 1
Step-by-step explanation: The first step is to add 6 to both sides of the equation to get -2b = -2
You then divide both sides by negative 2 so you can get a positive
dividing both sides by negative 2 will leave you with 1b = 1
so
b = 1
![\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides} \\\\\\ tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)](https://tex.z-dn.net/?f=%5Cbf%20tan%28x%5Eo%29%3D1.11%5Cimpliedby%20%5Ctextit%7Btaking%20%7Dtan%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28x%5Eo%29%5D%3Dtan%5E%7B-1%7D%281.11%29%5Cimplies%20%5Cmeasuredangle%20x%3Dtan%5E%7B-1%7D%281.11%29)
plug that in your calculator, make sure the calculator is in Degree mode
Answer:
= r²−4r+3
Step-by-step explanation:
(r - 3) (r - 1)
(r x r) + (r x -1) + (-3 x r) + (-3 x -1)
r² + - r - 3r + 3
= r²−4r+3