BE is parallel to CD, therefore, m∠BEC=m∠ECD, therefore mBC=mDE
BE is the diameter, so Arc BE is 180 degree
mBC+mCD+mDE=180
replace mCD with 3mBC, and replace mDE with mBC: mBC+3mBC+mBC=180
5mBC=180
mBC=180/5=36
mCD=3mBC=3*36=108
the inscirbed angle m∠ECD= the measure of arc DE=36
Answer:
2
Step-by-step explanation:
The height formula given is:
h = -16t^2 + 70
That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.
If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:
6 = -16t^2 + 70
16t^2 = 64
t^2 =4
t = 2 s
So, it will take 2 seconds for the object to be 6 feet above the valley floor.
Answer:
m∠1=80°
m∠2=112°
m∠3=131°
m∠4=80°
m∠5=37°
Step-by-step explanation:
First you have to find m∠2
To do that find m∠6 (I created this angle shown in pic below)
Find m∠6 by using the sum of all ∠'s in a Δ theorem
m∠6=180°-(63°+49°)
m∠6=68°
Now you can find m∠2 with the supplementary ∠'s theorem
m∠2=180°-68°
m∠2=112°
Then you find m∠5 using the sum of all ∠'s in a Δ theorem
m∠5=180°-(112°+31°)
m∠5=37°
Now you can find m∠1
m∠1=180°-(63°+37°)
m∠1=180°-100°=80°
m∠4 can easily be found too now:
m∠4=180°-(63°+37°)
m∠4=80°
m∠3=180°-49°
m∠3=131°
Answer:
The coordinate of 
is 13.36.
Step-by-step explanation:
According to the statement, we have the following information:
(1)
(2)
(3)
(4)
From (2), we have the following expression:
(5)
If we know that and , then the coordinate of is:
The coordinate of is 13.36.
You can change 24.5% by moving the decimal point
24.5%=.245
70,000 x .245=$17,150
