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8_murik_8 [283]
3 years ago
12

Please help me with this test I’m so bad at math

Mathematics
1 answer:
sattari [20]3 years ago
8 0

Answer:

4 is 13.75 and 5 is 14.704

Step-by-step explanation:

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 Which of the following are solutions to the equation below?
Novosadov [1.4K]

Answer:

The answer to your question is F

6 0
2 years ago
Given: ΔABC. If ∠B = 35°, a = 4.5 cm, and b = 6.0 cm, what is the measurement of ∠A to the nearest tenth of a degree?
soldier1979 [14.2K]
We know that

the law of sines established 
a/sin A=b/sin B--------sin A=[a*sin B]/b
a=4.5 cm
b=6 cm
B=35°
so
sin A=[4.5*sin 35°]/6-----> sin A=0.43018
A=arc sin(0.43018)-------> A=25.5°

the answer is the option
<span>C) 25.5° </span>


6 0
3 years ago
One side of a rectangle is 10 feet shorter than twice another side. Find the length of the shorter side if we also know the peri
seropon [69]

Answer:

  6 feet

Step-by-step explanation:

Let x represent the length of "another side." Then "one side" is ...

  2x -10 . . . . . . 10 feet shorter than twice another side

The sum of these two side lengths is half the perimeter, so is ...

  x + (2x -10) = 14 . . . . . two sides are half the perimeter

  3x = 24 . . . . . . . . . . . . add 10, collect terms

  x = 8 . . . . . . . . . . . . . . .divide by the coefficient of x

  (2x -10) = 2·8 -10 = 6 . . . . find "one side"

We have found "one side" to be 6 feet long, and "another side" to be 8 feet long. The shorter side is 6 feet.

8 0
3 years ago
Mrs. Sing bought a pound of green beans for $1.80. How much will Mrs. Tennison pay for 3 and 1/2 pounds of green beans?
statuscvo [17]
Mrs. sing will pay 6,30$ for 3 and 1/2 pounds of green beans

8 0
3 years ago
Read 2 more answers
Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.
FrozenT [24]
You have shared the situation (problem), except for the directions:  What are you supposed to do here?  I can only make a educated guesses.  See below:

Note that if    <span>ax^2+bx+5=0    then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers.  If this is the case, then the discriminant,    b^2 - 4(a)(c), must be positive.  Since c = 5, 

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then 

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

         - b plus sqrt( b^2 - 20a )
d =  ------------------------------------
                      2a

and

 </span>         - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
                      2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b."  Before going into that, however, I'm asking you to share the rest of the problem statement.  What, specificallyi, were you asked to do here?

7 0
3 years ago
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