Drag each expression to the phrase it best translates.

How do you sole this question kelpie sold cameras on her web site. She bought the cameras for $65 each included a 60% markup to

postnew [5]

So 65 dollars was what she paid
each camera INCLUDED a 60% mark UP so
she sold each at a 60% markup

65 dollars=100% of origonal camers
she sold them for 100+60=160% of origonal price
65 dollars=100%
percent means parts out of 100 so
160%=160/100=1.6

find 160% of 65
'of' means multiply so
1.6 times 65=104

she sold each camera at $104

4 0

3 years ago

Which list is in order from least to greatest?

Alex Ar [27]

|-9|, |-3.5|, |4.2| is the answer. row 3

7 0

4 years ago

People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear

Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

d.

α: 0.05

Left critical value: $t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306$

Right critical value: $t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306$

e.

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

X[bar]= 23

S= 3

$t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3$

f.

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!