Drag each expression to the phrase it best translates.

Suppose F⃗ (x,y)=⟨ex,ey⟩F→(x,y)=⟨ex,ey⟩ and CC is the portion of the ellipse centered at the origin from the point (0,1)(0,1) to

Rudik [331]

Probably the intended ellipse is the one with equation

$\dfrac{x^2}{49}+y^2=1$

We can parameterize $C$ as a piece of this curve by

$\vec r(t)=\langle7\sin t,\cos t\rangle$

with $0\le t\le\frac\pi2$ . Then

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^{\pi/2}\langle e^{7\sin t},e^{\cos t}\rangle\cdot\langle7\cos t,-\sin t\rangle\,\mathrm dt$

etc

7 0

4 years ago

Kate is baking pies for the teachers lunch at her school. She plans to give every teacher 16of a pie. She decides to bake10 pies

Mariulka [41]

Answer:

the answer is 260

Step-by-step explanation:

8 0

3 years ago

Find the Least Common Multiple (L.C.M) and Highest Common Factor (H.C.F) of 20 and 30.

Archy [21]

Answer:

LCM: 60

HCF: 10

Step-by-step explanation:

Listing Multiples

LCM:

Multiples of 20:

20, 40, 60, 80, 100

Multiples of 30:

30, 60, 90, 120

Therefore,

LCM(20, 30) = 60

----------------------------------------

Factorization

HCF:

The factors of 20 are: 1, 2, 4, 5, 10, 20

The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

Then the greatest common factor is 10

8 0

3 years ago

444919 to the nearest ten thousand

ehidna [41]

440000 is the answer because any thing under five turns into a zero and goes down

5 0

4 years ago

The Pew Forum on Religion and Public Life reported on Dec. 9, 2009, that in a survey of 2003 American adults, 25% said they beli

Nataly [62]

Answer:

The confidence interval at the 99% confidence level for the proportion of all adult Americans who believe in astrology is (0.2251, 0.2749). This means that we are 99% sure that the true proportion of all adult Americans who believe in astrology is in this interval.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$p = 0.25, n = 2003$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.25 - 2.575\sqrt{\frac{0.25*0.75}{2003}} = 0.2251$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.25 + 2.575\sqrt{\frac{0.25*0.75}{2003}} = 0.2749$

The confidence interval at the 99% confidence level for the proportion of all adult Americans who believe in astrology is (0.2251, 0.2749). This means that we are 99% sure that the true proportion of all adult Americans who believe in astrology is in this interval.

6 0

3 years ago