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aalyn [17]
3 years ago
9

Participant A did 120 jumping jacks in 10 minutes. Participant B did

Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:

Participant A

Step-by-step explanation:

Rate: jumping jacks per minute

Rate of A: 120jjs / 10mins = 12 jumping jacks per minute

Rate of B: 140jjs / 14mins = 10 jumping jacks per minute

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1. Simplify the expression<br> 11x + 3x
Natali [406]

Answer:

14x

Step-by-step explanation:

Step 1: Collect like terms by adding their coefficients

(11+3)x

Step 2: Add the numbers

14x

4 0
3 years ago
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Which expression is equivalent to (9x2y6)−1/2?
galben [10]

Answer:

B.  1/(3xy^3)

Step-by-step explanation:

The minus sign can be dealt with first, then the root taken.

\left(9x^{2}y^{6}\right)^{-\frac{1}{2}}=\dfrac{1}{\sqrt{9x^{2}y^{6}}}\\\\=\dfrac{1}{\sqrt{9}\sqrt{x^2}\sqrt{y^6}}=\dfrac{1}{3xy^3}

8 0
3 years ago
I need the answer because I can’t i need help
Free_Kalibri [48]

Answer:

3\frac{3}{4} , 4\frac{1}{4} , 4\frac{1}{2} (two x's on this spot), 5

Step-by-step explanation:

you need an x in each point (A, B, C, D, E) given in the chart

notice point B and E are the same

3\frac{3}{4} , 4\frac{1}{4} , 4\frac{1}{2} (two x's on this spot), 5

I believe the bottom left shows the right answer

7 0
3 years ago
WILL MARK BRAINLIEST!<br> What is the value of d?
liubo4ka [24]

Answer:

Step-by-step explanation:

The square indicates that the total angle is 90 degrees so

d+59=90

d=90-59

d=31 degrees

4 0
3 years ago
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Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

8 0
3 years ago
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