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aalyn [17]
3 years ago
9

Participant A did 120 jumping jacks in 10 minutes. Participant B did

Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:

Participant A

Step-by-step explanation:

Rate: jumping jacks per minute

Rate of A: 120jjs / 10mins = 12 jumping jacks per minute

Rate of B: 140jjs / 14mins = 10 jumping jacks per minute

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PLEASE HELP!!! WILL MARK AS BRAINLEIST <br> Which ones are linear and nonlinear<br> Picture bellow
OlgaM077 [116]

Linear equations are:

y=x+5

5x+5y=25

Non-linear equations are:

y = 2x^3

y=x^2-3

y=\frac{x^2}{2}

Step-by-step explanation:

Lets define linear and non-linear first.

Linear equation is that equation whose degree is one. Degree is the highest power of a variable in an expression or equation.

Similarly, an equation with degree greater than 2 are called non-linear equation

In the given equations,

y = 2x^3 => Degree: 3

y=x+5 => Degree: 1

y=x^2-3 => Degree: 2

5x+5y=25 => Degree:1

y=\frac{x^2}{2} => Degree:2

Hence,

Linear equations are:

y=x+5

5x+5y=25

Non-linear equations are:

y = 2x^3

y=x^2-3

y=\frac{x^2}{2}

Keywords: Linear equations, expressions

Learn more about linear equations at:

  • brainly.com/question/9969022
  • brainly.com/question/9801816

#LearnwithBrainly

8 0
4 years ago
Use the fact that the bacteria is doubling every five minutes. What fraction of the bottle was full at 11:20 a.m.?
oksian1 [2.3K]

Answer: D: 1/16

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A rectangular tank, 25 cm long and 25 cm wide is filled with water to a depth of 10 cm. When a metal cube of edge 10 cm is place
Sophie [7]

The problem involves the volume of the water of the rectangular tank, so first we must find the volume of our water. For the volume we have;

\begin{gathered} \text{Volume = Lenght x Width x Height} \\ V_{water}_{}_{}\text{ = 25 x 25 x 10} \\ V_{water}=6250cm^3 \end{gathered}

Therefore our tank has an initial volume of 6250 cm³, but if you drop a cube with a side measuring 10 cm. the volume of the water in our tank increases. Giving us the expression;

\begin{gathered} \text{Volume Combined = Volume of Water + Volume of Cube} \\ V_{comb}=V_{water}+V_{cube} \end{gathered}

Since we already have the volume of the water (which is 6250), we just need to find the volume of the cube using the same formula (<em>Volume = Lenght x Width x Height</em>);

\begin{gathered} V_{comb}=V_{water}+V_{cube} \\ V_{comb}=V_{water}+(Lenght_{cube})(Width_{cube})(Height_{cube})_{}_{}_{} \\ V_{comb}=V_{water}+10(10)(10) \\ V_{comb}=6250+1000 \\ V_{comb}=7250cm^3 \end{gathered}

Therefore our new volume when they are combined or when the cube is droped in the tank is 7250 cm³.

But we must remember since our tank would remain it's shape no matter how much water it holds it would always retain it's dimension of it's lenght and width (25x25), therefore it is possible to find the height of the new water level using this logic;

\begin{gathered} V_{comb}=(Length_{\tan k})(Width_{\tan k})(Height_{water}\text{)} \\ V_{comb}=(25)(25)(Height_{water})\text{ , with our }V_{comb}=7250 \\ 7250=625(Height_{water}) \\ \text{Height}_{water}=\frac{7250}{625} \\ \text{Height}_{water}=11.6\text{ cm} \end{gathered}

Therefore the height of the new water level is 11.6 cm.

7 0
1 year ago
I need help!!!
Kruka [31]

Answer: x = -3/4 can not be a rational zero of the polynomial.

Step-by-step explanation:

We have the polynomial:

6x^5 + ax^3 -bx -12 = 0.

The theorem says that:

If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).

The factors of -12  (different than itself) are (independent of the sign).

1, 2, 3, 4 and 6.

So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.

The factors of 6 are:

1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.

Then the option that can not be a zero of the polynomial is

x = -3/4

because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.

4 0
4 years ago
To the nearest hundredth, what is the distance between point (-6, -1) and point (4, 3)?
vagabundo [1.1K]
Use the distance formula and simply substitute in the corresponding orders pairs.

Distance = √(x2 - x1)² + (y2 - y1)²

Distance = √(4 - (-6))² + (3 - (-1))²

Distance = √(4 + 6)² + (3 + 1)²

Distance = √(10)² + (4)²

Distance = √100 + 16

Distance = √116

Distance = 10.7703296143

Round to the nearest hundredth!

Distance ≈ 10.77
5 0
3 years ago
Read 2 more answers
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