Answer:
Mean x¯¯¯ 2.2
Median x˜ 1
Range = 9
Q1 --> 0
Q2 --> 1
Q3 --> 3
Interquartile range: 3
Mean Absolute Deviation (MAD): 2.08
Standard deviation : 2.71
Step-by-step explanation:
1. Number of absent students:
0,1,1,0,3,2,5,1,9,0
Find the:
Mean
0, 0, 0, 1, 1, 1, 2, 3, 5, 9/10
= 22/10
= 2.2
Median
0, 0, 0, 1), 1, 1, (2, 3, 5, 9
= 1 + 1/2
= 2/2
= 1
Lower quartile
Upper quartile
Range
= 9 - 0
= 9
Interquartile range = 3
Mean absolute deviation = 2.08
Standard deviation = 2.71
