Given the function:
The function can also be written as:
The range of the function will be all set of y values.
To find the range, let's graph the function below.
We have:
From the graph above, all possibe y values range from 0 to infinity.
Therefore, the range of the function is from zero infinity.
In interval notation:
Range = (0, +∞)
ANSWER:
4. (0, +∞)
Hey Jinx :)
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Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.
y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH
y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY
y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH
y = 200(0.73)^t → (Rate is between 0 and 1) DECAY
y = 4(1/4)^t → (Rate is between 0 and 1) DECAY
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Hope This Helped! Good Luck!
Answer:
0
Step-by-step explanation:
–5(3 – q) + 4 = 5q – 11
-15 +5q + 4 = 5q -11
-11 + 5q = 5q - 11
+5q - 5q = -11 + 11
0=0
Answer:
$80, $48
Step-by-step explanation:
The original price was x.
The price is reduced by 40%. The markdown is 40% of x, or 0.4x.
The actual dollar amount of the markdown is $32.
That means that 0.4x must equal $32.
We set up an equation and solve for x, the original price.
0.4x = 32
Divide both sides by 0.4
x = 32/0.4
x = 80
The original price is $80.
The markdown is $32.
$80 - $32 = $48
The marked down price is $48.
Answer: $80, $48
