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hjlf
3 years ago
13

Find the coordinates of the vertex for the parabola -x^2-4+7

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0
-X²-4+7
=-X²+3
a=-1 b=0
X=-b/2a
X=0
If X=0, Y=3
So the Vertex is (0, 3).
That's your answer.
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The table shows the steps for solving the given inequality for x. −2(3−2x)
Delicious77 [7]

Answer:

3x = 4-x "hope this helps"

Step-by-step explanation:

4 0
4 years ago
6/5 s = -2 <br><br> whats the answer solve the (s)
iVinArrow [24]

Answer: s= -5/3

Step-by-step explanation: hope this helps!

7 0
3 years ago
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Jake is solving x^2-6x+5=0 by completing the square his steps are shown below step 1. x^2-6x=-5 step 2. x^-6x+9=-5+9 step 3. (x-
damaskus [11]

Answer:

Jake's error in step 3

Step-by-step explanation:

we have

x^{2} -6x+5=0

Complete the square

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2} -6x=-5

step 2

Complete the square. Remember to balance the equation by adding the same constants to each side

x^{2} -6x+9=-5+9

x^{2} -6x+9=4

step 3

Rewrite as perfect squares

(x-3)^{2}=4

Jake's error in step 3

He placed 6 instead of 3 in the left side

step 4

take square root both sides

\sqrt{(x-3)^2} =\sqrt{4}

step 5

(x-3)=\pm2

step 6

x=3\pm2

step 7

x=5 and x=1

7 0
4 years ago
What is the equation of the line perpendicular to Y-3x+1 that passes through the point (12,-6)?
erma4kov [3.2K]

Answer:

3y + x = -6

Step-by-step explanation:

Given

y = 3x + 1

Required

Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1

First, the slope of the line has to be calculated;

Th slope of a line is the coefficient of x in its linear equation;

This implies that the slope of y = 3x + 1 is 3

Having calculated the slope of the first line;

The relationship between both lines are perpendicularity; this implies that m_1 * m_2 = -1

Where m_1 = 3 and m_2 is the slope of the secodnd line

m_1 * m_2 = -1 becomes

3 * m_2 = -1

Divide both sides by 3

\frac{3 *m_2}{m_2} = \frac{-1}{3}

m_2 = \frac{-1}{3}

The equation of the line can be calculated using the folloing formula

m = \frac{y - y_1}{x - x_1}

Where (x_1, y_1) = (12,-6) and m_2 = \frac{-1}{3}

The equation becomes

\frac{-1}{3} = \frac{y -- 6}{x - 12}

\frac{-1}{3} = \frac{y + 6}{x - 12}

Cross multiply

-(x - 12)= 3(y + 6)

-x + 12=3y + 18

Collect like terms

12 - 18 = 3y +x

-6 = 3y + x

3y + x = -6

4 0
3 years ago
Hi! can anyone help me? Question is down in the picture below! 10 points! Thank you!
Bad White [126]

Answer:2

Step-by-step explanation:

I’m not exactly sure bc I’ve never heard a problem like that before but I believe that’s correct.

5 0
2 years ago
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