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Over [174]
3 years ago
10

NEED HELP!! NO LINKS PLS

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

(3x-4)(5x+2)

Step-by-step explanation:

You might be interested in
A GMC dealer believes that demand for 2005 Envoys will be normally distributed with a mean of 200 and standard deviation of 30.
irina1246 [14]

Answer:

The correct answer to the following question will be "280 units".

Step-by-step explanation:

The given values are:

Mean = 200

Standard deviation = 30

Let's ask that the supplier needs to reach 99.9% of the standard of operation. To reach this quality of operation, she has to preserve an inventory of

Now,

⇒  Mean + 3\times sigma

On putting the values, we get

⇒  200+3\times 30

⇒  200+90

⇒  290 \ units

290 units would then accomplish a level of service of 99.9%.

Half unpurchased units can indeed be purchased at $30000 i.e. no failure. If he requests 300, there will be losses on 5 products that are unsold.

Hence, ordering 280 units seems to be preferable

3 0
3 years ago
PLEASE HELP ME !!!!!!!!!!!!!!!!!!!!!
dsp73

Answer:

the required answer is 64

Step-by-step explanation:

b/4 =16

b = 16 × 4

= 64

7 0
2 years ago
Read 2 more answers
He mean potassium content of a popular sports drink is listed as 140 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sa
mezya [45]

Answer: (A) H0: μ = 140 mg vs. H1: μ ≠ 140 mg

Step-by-step explanation:

Usually null hypothesis represents the claim that the values associated to the groups being tested have no statistical difference but alternative hypothesis supports the claim that there is statistical difference.

Let \mu be the population mean .

We are given that the mean potassium content of a popular sports drink is listed as 140 mg in a 32-oz bottle.

i.e. Null hypothesis :H_0:\mu=140

Alternative hypothesis for two tail hypothesis has sign (≠).

i.e. Alternative hypothesis : H_1 : \mu\neq140

∴ The hypotheses for a two-tailed test of the claimed potassium content:

H0: μ = 140 mg vs. H1: μ ≠ 140 mg

3 0
3 years ago
May someone help me with 2-9? Please?
mylen [45]

2. Each side of a pentagon is the same size.

4cm x 5 = 20cm or 4cm+4cm+4cm+4cm+4cm = 20cm

3. Each side of a square is the same size.

13yd x 4 = 52yd or 13yd+13yd+13yd+13yd = 52yd

4. Add all sides together.

12m+12m+30m+30m = 84m

5. Again add all sides together.

16yd+16yd+4yd+4yd = 40yd

6. Each side of a square is the same size.

7in x 4 = 28in. or 7in+7in+7in+7in = 28in

7. Add all sides together.

2cm+2cm+3cm+3cm = 10cm

8. Each side of a rhombus is the same size. A rhombus has 4 sides.

23in x 4 = 92in or 23in+23in+23in+23in = 92in

9. A regular octagon has 8 sides and each side is the same size.

9cm x 8 = 72cm

7 0
3 years ago
What is the relationship between the number of vertices in each polygon and the number of isosceles triangles?
marshall27 [118]

Answer:

You didn’t post the figures so I’ll guess C lol

Step-by-step explanation:

5 0
3 years ago
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