70 ft per sec going upward 3 sec from 6 ft high should reach 216 ft, but unfortunately gravity is pulling it and at some point it starts to go backward (at 2.176 second), so to compensate the upward slowing down and distance dropped, use -32.176 times 3 square times 1/2 = -144.792 which is the natural drop distance if the football is released mid air without a initial speed after 3 seconds. 216 - 144.792 = 71.208 ft high.
Answer:
0.14
Step-by-step explanation:
P(A|B) asks for the probability of A, given that B has happened. This is equal to the probability of A and B over the probability of B (see picture)
Here, the question is asking if someone is taking the bus given that they are a senior.
The probability of someone being a senior and taking the bus is 5/100, or 0.05 . The probability of someone being a senior is 35/100, or 0.35
Our answer is then 0.05/0.35 = 1/7 = 0.14
You are asked to do this problem by graphing, which would be hard to do over the Internet unless you can do your drawing on paper and share the resulting image by uploading it to Brainly.
If this were homework or a test, you'd get full credit only if you follow the directions given.
If <span>The points(0,2) and (4,-10) lie on the same line, their slope is m = (2+10)/(-4), or m =-3. Thus, the equation of this line is y-2 = -3x, or y = -3x + 2.
If </span><span>points (-5,-3) and (2,11) lie on another line, the slope of this line is:
m = 14/7 = 2. Thus, the equation of the line is y-11 = 2(x-2), or y = 11+2x -4, or y = 2x + 7.
Where do the 2 lines intersect? Set the 2 equations equal to one another and solve for x:
</span>y = -3x + 2 = y = 2x + 7. Then 5x = 5, and x=1.
Subst. 1 for x in y = 2x + 7, we get y = 2(1) + 7 = 9.
That results in the point of intersection (2,9).
Doing this problem by graphing, on a calculator, produces a different result: (-1,5), which matches D.
I'd suggest you find and graph both lines yourself to verify this. If you want, see whether you can find the mistake in my calculations.
