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Suppose we have a triangle ΔABC,
Length of AB = 14
Length of AC = 14
Angle ∠BAC = 122 degree
This triangle is isosceles triangle so, angle B = angle C = (180 - 122)/2 = 29
We know the two side and one angle of triangle ABC, here we use Sine Rule.
(In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of a triangle (any shape) to the sines of its angles.)
According to the law,
Solve for a
a = 24.49 option C
You can use the definition of prime polynomials to find out which polynomial is prime and which is not.
The prime polynomials in the given options are:
Option 1:
Option 3:
Those polynomials with integer coefficients that cannot be factored further, with factors of lower degree and integer coefficients are called prime polynomial.
(it is necessary that no factors exists having their coefficients are still integers and they're of lower degree)
<h3>Which of the given polynomials are prime?</h3>Option 1:
We have to check it manually. The roots of this equation are
not integer or integer fraction (checked from calculator), and does't factor into smaller integer coefficient polynomials.
(you can check if its getting factored, manually, and most of the times, if it is not prime, it will get factored).
Thus, it is a prime polynomial.
Option 2:
We can rewrite it as
Thus, it is possible to write it as product of lower degree polynomial with integer coefficients, thus it is not a prime polynomial.
Option 3:
Since 3 is prime number and since given polynomial is quadratic thus lower degree would be only linear, thus, let
b is not a real number, so the factorization is not polynomial factorization.
Thus, it is prime polynomial.
Option 4:
We can rewrite it as:
Thus, not a prime polynomial.
Option 5:
We can rewrite it as:
Thus, not a prime polynomial.
Thus,
The prime polynomials in the given options are:
Option 1:
Option 3:
Learn more about prime polynomials here: