Sort of. Both the best though
Answer: true
Step-by-step explanation:
Answer:
Correct option:
"z requires that you know the population standard deviation σ which may be unrealistic."
Step-by-step explanation:
The hypothesis test for significant population mean <em>μ</em> can be done either using the <em>z</em>-distribution of <em>t</em>-distribution.
Both the distribution require certain conditions to be fulfilled to use.
For using a <em>z</em>-distribution to perform a hypothesis test for <em>μ</em> the conditions to fulfilled are:
- Population is Normally distributed.
- The population standard deviation is known.
- The sample selected is large.
For using a <em>t</em>-distribution to perform a hypothesis test for <em>μ</em> the conditions to fulfilled are:
- Population is Normally distributed.
- The sample selected is randomly selected.
If the population standard deviation is not known and we have to compute the sample standard deviation then use the <em>t</em>-distribution to perform the test for population mean.
Thus, the correct option is:
"z requires that you know the population standard deviation σ which may be unrealistic."
Answer:
n(A) = 3
n(B) = 6
-6 ∈ A => True
-14 ∈ A => False
k ∈ B=> True
Q∈B = >False
Step-by-step explanation:
Given
A is the set of integers greater than - 7 and less than - 3
B={c, h, j, k, v, y}
For set A:
The integers greater than -7 will be -6,-5 ....
As the set has integers less than -3, the set will be:

<u>Cardinalities:</u>
Cardinality is the number of elements in the set.
So,

Now for the statements:
-6 ∈ A True as -6 is a member of set A
-14 ∈ A False as -14 is not a member of A
k ∈ B True
Q∈B False
Hence,
n(A) = 3
n(B) = 6
-6 ∈ A => True
-14 ∈ A => False
k ∈ B=> True
Q∈B = >False
Hi there,
This is the original equation:

First, we need to subtract 5 from both sides;

Then, we subtract 8v from both sides;

Finally, divide both sides by -2;

Therefore, the answer to your problem is
v = -3. Hope this helps and have a great day!