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Black_prince [1.1K]
3 years ago
9

Which units would be used for a measurement of area? cm 2 π inches ft 3

Mathematics
1 answer:
netineya [11]3 years ago
7 0
I believe cm. I’m not quite sure tho i don’t think it would be pi.
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PQRS is a parallelogram. Answer the questions below.
abruzzese [7]

Answer:

4. SR= 17 (opposite angle of parallogram are equal)

8 0
2 years ago
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
1 year ago
Fred is trying to earn $35 to buy a basketball. He has saved $11.25. He earns $2.25 per hour doing yard work for his neighbor, a
rjkz [21]
2.25y + 7.25z + 11.25  \geq 35 \\ y = 2 \\ z = 3 \\ 2.25(2) + 7.25(3) + 11.25 \geq 35 \\ 4.50 + 21.75 + 11.25  \geq 35 \\ 37.5  \geq 35
The answer will be the third one: Yes, because the total will be $37.50.
7 0
2 years ago
-0.615, -5/8, -0.62 least to greatest
ludmilkaskok [199]

Answer:

-5/8,  -0.62, -0.615

Step-by-step explanation:

For -5/8, dividing -5 by 8 will result in -0.63, that's why it's the least (the farthest negative number from 0).

Next is -0.62

Since -0.615 isn't rounded up to the nearest hundredths, it is the greatest because it's closest to 0.

5 0
3 years ago
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