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Ivahew [28]
3 years ago
10

Tyreek Hill has scored 32 touchdowns in 59 games. If he continues at this rate, how many touchdowns will he score in the 2020 se

ason where he plays 16 games? Write the equation.​
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

Answer:

hi            

Step-by-step explanation:

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Consider the Inequality <br> —2n +7 &gt; -11<br> What is the solution of the inequality
Marta_Voda [28]

Answer:

  • n < 9 or n = (-oo, 9)

Step-by-step explanation:

  • -2n +7 > -11
  • -2n > -11 - 7
  • -2n > -18
  • n < -18/-2
  • n < 9
  • n = (-oo, 9)
5 0
3 years ago
Please solve this question on rationalising denominators showing all working &lt;3
Komok [63]

Step-by-step explanation:

denominators showing all working <3

8 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.
valentinak56 [21]
246/1000 or 123/500 hope this helps
5 0
3 years ago
Read 2 more answers
What is 3 3/8 +3 1/2 using common denominator
horrorfan [7]
1/2=4/8. 3 and 4/8+ 3 and 3/8 is 6 and 7/8.
8 0
3 years ago
Read 2 more answers
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