Y = cube root of 27
another answer is
<span>y equals square root of 27 divided by 3
Provided it is </span><span>square root of (27 divided by 3)
</span>
Answer:
197
Step-by-step explanation:
You have 6 sides of this object. So we will calculate six surface areas.
P1=5x5=25 ( on the top)
P2=9x5=45 ( on the bottom)
P3= 5x5= 25 (left side)
P4=6,4x5=32 (rightside)
P5= (9+5)x5/2=70/2=35 ( front trapeze)
P6=P5=35 ( behided trapeze)
P= p1+p2+p3+p4+p5+p6=
25+45+25+32+35+35 =197
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
#SPJ4
At x intercept , y = 0 so we have
6x - 3(0) = 24
6x = 24
x = 4 Answer