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2 years ago

Help plsss ! 10 points !

Mathematics

1 answer:

dybincka [34]2 years ago

3 0

Answer:

They are The Same if you note 1 square = 1 square cm,They all are 10square cm

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The line with equation y = 2x - 6 passes through the point (a,2). The value of a is:

guapka [62]

Answer:

b) 4

Step-by-step explanation:

4 0

2 years ago

H^-16/h^x=1/h^24 can someone help me please

Basile [38]

Given:

Consider the equation is

$\dfrac{h^{16}}{h^x}=\dfrac{1}{h^{24}}$

To find:

The value of x.

Solution:

We have,

$\dfrac{h^{-16}}{h^x}=\dfrac{1}{h^{24}}$

Using properties of exponents, we get

$h^{-16-x}=h^{-24}$ $[\because \dfrac{a^m}{a^n}=a^{m-n},a^{-n}=\dfrac{1}{a^n}]$

On comparing both sides, we get

$-16-x=-24$

Add 16 on both sides.

$-x=-24+16$

$-x=-8$

Multiply both sides by -1.

$x=8$

Therefore, the value of x is 8.

5 0

2 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$