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topjm [15]
3 years ago
15

Please help help help help please

Mathematics
2 answers:
solniwko [45]3 years ago
7 0

Answer: A

Step-by-step explanation:

ahrayia [7]3 years ago
3 0

The answer for this question is (-3,-2)

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Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.
Over [174]

Solution:

Formula for radioactive Decay is given by

R_{0}= R(1-\frac{S}{100})^t

R_{0}= Initial Population

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Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64→→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

15=(15+k)(1-\frac{35}{100})^{3.64+t}→→→  Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.







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3 years ago
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Find the equation of the line that passes through (-18, -10) and is parallel to the line that passes through (-2, 2) and (-8, 1)
zhuklara [117]

Answer:

y = 1/6x + 7/3

Step-by-step explanation:

(-2 ,2) and (-8, 1)

Slope=(1-2)/(-8- - 2) = (-1/-6) = 1/6

b = 2 - (1/6)(-2) = 2 - 2/6 = 2 - 1/3 = 7/3

5 0
2 years ago
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