The spread around a regression modle is measured with the residual standard deviation. True or False

Mathematics

1 answer:

Anna11 [10]3 years ago

3 0

Answer:

True

Step-by-step explanation:

Residual standard deviation is the square root of the residual variance. It is an estimate of the error made on the measurement of the dependent variable.

Thus, the spread around the regression model is usually measured with the residual standard deviation because it is the measurement of standard error between actual and predicted value.

You might be interested in

7w + 6 + 2w = _ (w + 2)

gayaneshka [121]

Answer:

7(-1/2 +2) = -6(2(-1/2) -1) +3(-1/2)

7(3/2) = -6(-2) -3/2

21/2 = 12 -3/2 . . . . . true, answer checks OK

Step-by-step explanation:

3 0

3 years ago

Pedro and Carmela are cleaning their kitchen. It takes Pedro 3 hours to clean the kitchen by himself, while Carmela can clean th

Igoryamba

Answer:

Step-by-step explanation:

Here, we want to choose the equation representing the time it will take if they worked together

Let the amount of tasks to be done be t

pedro will work at a rate of t/3

Camela will take t/2

So the joint rate will be

t/2 + t/3

This joint rate will be equal to 1

Thus, we have

t/2 + t/3 = 1

5 0

3 years ago

Find S15 for the geometric series 72 + 12 + 2 + +…

Sedbober [7]

$S_{15}=72+12+\cdots+\dfrac1{181398528}+\dfrac1{1088391168}$
$S_{15}=72\left(\dfrac16\right)^0+72\left(\dfrac16\right)^1+\cdots+72\left(\dfrac16\right)^{13}+72\left(\dfrac16\right)^{14}$
$S_{15}=72\displaystyle\sum_{i=1}^{15}\left(\frac16\right)^{i-1}$

$\dfrac16S_{15}=72\displaystyle\sum_{i=1}^{15}\left(\frac16\right)^i$

$\implies S_{15}-\dfrac16S_{15}=72\displaystyle\sum_{i=1}^{15}\bigg(\left(\dfrac16\right)^{i-1}-\left(\dfrac16\right)^i\bigg)$
$\dfrac56S_{15}=72\bigg(\left(1-\dfrac16\right)+\left(\dfrac16-\dfrac1{6^2}\right)+\cdots+\left(\dfrac1{6^{13}}-\dfrac1{6^{14}}\right)+\left(\dfrac1{6^{14}}-\dfrac1{6^{15}}\right)\bigg)$
$\dfrac56S_{15}=72\left(1-\dfrac1{6^{15}}\right)$
$S_{15}=\dfrac{432}5\times\dfrac{6^{15}-1}{6^{15}}=86.4$